When $$a \ne 0$$, there are two solutions to $$ax^2 + bx + c = 0$$ and they are $x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$ $Text\ Spaces =$

$Keliling\ Persegi\ Panjang = { 2p + 2l } { \ atau\ } { 2 (p+l) }$

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